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Support CenterKnowledge Base ArticlesCode-check of bolts according to Indian standard
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Code-check of bolts according to Indian standard
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Bolts are checked for shear, bearing, tension capacity, and for combined tension and shear. Structural design of bolted steel connections.
SteelConnection designKnowledge baseIS (India)Connection

Code-check of bolts according to Indian standard

This article is also available in
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Bolts are checked for shear, bearing, tension capacity and for combined tension and shear.

Shear capacity of bolts

The design strength of the bolt, VdsbV_{dsb}Vdsb​, as governed shear strength is given by IS 800, Cl. 10.3.3:

Vsb≤VdsbV_{sb} \le V_{dsb}Vsb​≤Vdsb​

where:

  • Vdsb=Vnsb/γmbV_{dsb} = V_{nsb}/\gamma_{mb}Vdsb​=Vnsb​/γmb​ – design shear capacity of a bolt
  • Vnsb=fub3AeV_{nsb} = \frac{f_{ub}}{\sqrt{3}} A_eVnsb​=3​fub​​Ae​ – nominal shear capacity of a bolt
  • fubf_{ub}fub​ – ultimate tensile strength of a bolt;
  • AeA_eAe​ – area for resisting shear; Ae=AnA_e = A_nAe​=An​ for shear plane intercepted by the threads, Ae=AsA_e = A_sAe​=As​ for the case where threads do not occur in shear plane
  • AnA_nAn​ – net tensile stress area of the bolt
  • AsA_sAs​ – cross-section area at the shank
  • γmb=1.25\gamma_{mb} = 1.25γmb​=1.25 – partial safety factor for bolts – bearing type – IS 800, Table 5; editable in Code setup

When the grip length of bolts lgl_glg​ (equal to the total thickness of the connected plates) is higher than 5d5d5d, the design shear capacity VdsbV_{dsb}Vdsb​ is reduced by a factor βlg\beta_{lg}βlg​ – IS 800, Cl. 10.3.3.2:

βlg=83+lg/d\beta_{lg} = \frac{8}{3+l_g/d}βlg​=3+lg​/d8​

According to IS 800, Cl. 10.3.3.3, the design shear capacity of bolts carrying shear through a packing plate with the thickness tpk≄6t_{pk} \ge 6tpk​≄6 mm shall be decreased by a factor:

βpk=(1āˆ’0.0125tpk)\beta_{pk} = (1-0.0125 t_{pk})βpk​=(1āˆ’0.0125tpk​)

Each shear plane is checked separately, and the worst result is shown.

Bearing capacity of bolts

The design bearing strength of a bolt on any plate, as governed by bearing is given by IS 800, Cl. 10.3.4:

Vsb≤VdpbV_{sb} \le V_{dpb}Vsb​≤Vdpb​

where:

  • Vdpb=Vnpb/γmbV_{dpb} = V_{npb} / \gamma_{mb}Vdpb​=Vnpb​/γmb​ – design bearing strength of a bolt
  • Vnpb=2.5kbdtfuV_{npb} = 2.5 k_b d t f_uVnpb​=2.5kb​dtfu​ – nominal bearing strength of a bolt
  • kb=min⁔{e3d0, p3d0āˆ’0.25, fubfu, 1.0}k_b = \min \left \{ \frac{e}{3d_0}, \, \frac{p}{3d_0}-0.25, \, \frac{f_{ub}}{f_u}, \, 1.0 \right \}kb​=min{3d0​e​,3d0​pā€‹āˆ’0.25,fu​fub​​,1.0} – factor for joint geometry and material strength
  • eee – end distance of the fastener along bearing direction
  • ppp – pitch distance of the fastener along bearing direction
  • fubf_{ub}fub​ – ultimate tensile strength of the bolt
  • fuf_ufu​ – ultimate tensile strength of the plate
  • ddd – nominal diameter of the bolt
  • d0d_0d0​ – diameter of bolt hole
  • ttt – plate thickness
  • γmb=1.25\gamma_{mb} = 1.25γmb​=1.25 – partial safety factor for bolts – bearing type – IS 800, Table 5; editable in Code setup

Bearing on each plate is checked separately and the worst result is shown.

The bearing resistance is reduced for oversized and slotted holes by a factor:

  • 0.7 – for oversized and short slotted holes
  • 0.5 – for long slotted holes

Sizes of oversized, short slotted, and long slotted holes are determined according to IS 800, Table 19.

Tension capacity of bolts

A bolt subjected to a factored tensile force is checked according to IS 800, Cl. 10.3.5:

Tb≤TdbT_b \le T_{db}Tb​≤Tdb​

where:

  • Tdb=Tnb/γmbT_{db} = T_{nb} / \gamma_{mb}Tdb​=Tnb​/γmb​ – design tensile capacity of the bolt
  • Tnb=min⁔{0.9fubAn, fybAs(γmb/γm0)}T_{nb} = \min \{ 0.9 f_{ub} A_n, \, f_{yb} A_s (\gamma_{mb} / \gamma_{m0}) \}Tnb​=min{0.9fub​An​,fyb​As​(γmb​/γm0​)} – nominal tensile capacity of the bolt
  • fubf_{ub}fub​ – ultimate tensile strength of the bolt
  • fybf_{yb}fyb​ – yield strength of the bolt
  • AnA_nAn​ – net tensile stress area of the bolt
  • AsA_sAs​ – cross-section area at the shank
  • γmb=1.25\gamma_{mb} = 1.25γmb​=1.25 – partial safety factor for bolts – bearing type – IS 800, Table 5; editable in Code setup
  • γm0=1.1\gamma_{m0} = 1.1γm0​=1.1 – partial safety factor for resistance governed by yielding – IS 800, Table 5; editable in Code setup

Bolt subjected to combined shear and tension

A bolt required to resist both design shear force and design tensile force at the same time shall according to IS 800, Cl. 10.3.6 satisfy:

(VsbVdb)2+(TbTdb)2≤1.0\left( \frac{V_{sb}}{V_{db}} \right)^2 + \left( \frac{T_{b}}{T_{db}} \right)^2 \le 1.0(Vdb​Vsb​​)2+(Tdb​Tb​​)2≤1.0

where:

  • VsbV_{sb}Vsb​ – factored shear force
  • Vdb=min⁔{Vdsb, Vdpb}V_{db} = \min \{ V_{dsb}, \, V_{dpb} \}Vdb​=min{Vdsb​,Vdpb​} – design shear resistance of the bolt – IS 800, Cl. 10.3.2
  • VdsbV_{dsb}Vdsb​ – design shear resistance
  • VdpbV_{dpb}Vdpb​ – design bearing resistance
  • TbT_bTb​ – factored tensile force
  • TdbT_{db}Tdb​ – design tensile capacity of the bolt

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